What is the change in velocity for a ball 2 seconds after reaching its highest point?

To understand the change in velocity of the ball 2 seconds after reaching its highest point, it is essential to consider the motion of a projectile under the influence of gravity. When the ball reaches its highest point, its velocity is momentarily zero, indicating that it has stopped ascending and is about to descend.

After reaching this point, the only force acting on the ball is the force of gravity, which causes it to accelerate downward. In a gravitational field near the Earth's surface, the acceleration due to gravity is approximately 9.81 m/s², which can be rounded to 10 m/s² for ease of calculations.

In the context of the question, we are specifically examining the change in velocity over a 2-second interval. Since the acceleration is approximately -10 m/s² (the negative sign indicates that the acceleration is directed downward), the velocity changes at this rate.

Over 2 seconds, the velocity change can be calculated as: Change in velocity = acceleration × time Change in velocity = (-10 m/s²) × (2 s) = -20 m/s

This result indicates that the ball's velocity has changed by -20 m/s in the downward direction after 2 seconds. Therefore, the correct answer, representing