If the force of friction on a crate is 70N, what is the net work done leading to the kinetic energy gained?

To determine the net work done that leads to the kinetic energy gained in this scenario, it's important to recognize that work and energy are closely related through the work-energy principle. This principle states that the work done on an object is equal to the change in its kinetic energy.

In this case, the force of friction acting on the crate is 70 N. However, the net work done is not simply equal to the force of friction; rather, it should take into account the distance over which this force acts. If the kinetic energy gained by the crate is directly derived from the net work done against the frictional force, the net work must have a specific magnitude determined by this frictional force and the distance moved.

If the force of friction results in 70 N preventing the acceleration and thus the movement towards kinetic energy while any applied force is moving the crate, then we must ensure we know how far the crate moved under that friction. If the movement resulted in a calculated kinetic energy gain of 300J, one would have to have distance and possibly a larger applied force to overcome that friction, thus leading to the energy gained that could be reflected in kinetic energy.

If the crate has an acceleration due to a net force overcoming friction, it would imply