How much work is done when pushing a crate horizontally with a force of 90N across a distance of 15m?

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Enhance your knowledge for the ASU PHY101 Exam. Prepare with multiple choice questions, flashcards, and explanations. Get exam ready with ease!

To determine the work done when pushing a crate, we utilize the formula for work, which is defined as the product of the force applied and the distance over which that force is applied, specifically when the force and distance are in the same direction. The formula can be expressed as:

[ \text{Work} = \text{Force} \times \text{Distance} ]

In this scenario, the force exerted on the crate is 90 Newtons, and the distance over which this force is applied is 15 meters. Plugging these values into the formula gives us:

[ \text{Work} = 90 , \text{N} \times 15 , \text{m} ]

Calculating this yields:

[ \text{Work} = 1350 , \text{Joules} ]

Thus, the correct amount of work done while pushing the crate is indeed 1350 Joules. This illustrates the relationship between force and distance in the context of work, confirming how the work performed increases with either a greater force or a longer distance. The other choices, therefore, do not reflect the accurate calculation based on the given parameters.

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